9n^2-612=0

Solution for 9n^2-612=0 equation:

9n^2-612=0

a = 9; b = 0; c = -612;
Δ = b2-4ac
Δ = 02-4·9·(-612)
Δ = 22032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22032}=\sqrt{1296*17}=\sqrt{1296}*\sqrt{17}=36\sqrt{17}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{17}}{2*9}=\frac{0-36\sqrt{17}}{18}
=-\frac{36\sqrt{17}}{18}
=-2\sqrt{17}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{17}}{2*9}=\frac{0+36\sqrt{17}}{18}
=\frac{36\sqrt{17}}{18}
=2\sqrt{17}
$